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		<title>NCERT Solutions Class 9 Maths Chapter 12 Quadrilaterals on Padhaiwise</title>
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				<title>NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 12 Quadrilaterals Exercise Set 12.1</title>
				<link>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/exercise-set-12.1/</link>
				<pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
				<guid>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/exercise-set-12.1/</guid>
				<description>&lt;h1 id=&#34;ncert-solutions-for-class-9-maths-chapter-12--exercise-set-121&#34;&gt;NCERT Solutions for Class 9 Maths Chapter 12 — Exercise Set 12.1&lt;a class=&#34;anchor&#34; href=&#34;#ncert-solutions-for-class-9-maths-chapter-12--exercise-set-121&#34;&gt;#&lt;/a&gt;&lt;/h1&gt;&#xA;&lt;p&gt;&lt;strong&gt;Definition (from the book):&lt;/strong&gt; for four distinct points $A, B, C, D$ in a plane, with no three collinear, the points on segments $AB$, $BC$, $CD$, $DA$ form &lt;strong&gt;quadrilateral ABCD&lt;/strong&gt; if every such point other than $A, B, C, D$ lies on exactly one of these segments. A quadrilateral is &lt;strong&gt;convex&lt;/strong&gt; when all its internal angles are less than 180° — equivalently, when its diagonals intersect.&lt;/p&gt;</description>
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				<title>NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 12 Quadrilaterals Exercise Set 12.2</title>
				<link>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/exercise-set-12.2/</link>
				<pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
				<guid>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/exercise-set-12.2/</guid>
				<description>&lt;h1 id=&#34;ncert-solutions-for-class-9-maths-chapter-12--exercise-set-122&#34;&gt;NCERT Solutions for Class 9 Maths Chapter 12 — Exercise Set 12.2&lt;a class=&#34;anchor&#34; href=&#34;#ncert-solutions-for-class-9-maths-chapter-12--exercise-set-122&#34;&gt;#&lt;/a&gt;&lt;/h1&gt;&#xA;&lt;blockquote class=&#39;book-hint important&#39;&gt;&#xA;&lt;p&gt;&lt;strong&gt;Theorem 1:&lt;/strong&gt; In a parallelogram, (a) opposite sides are equal, (b) opposite angles are equal, (c) the diagonals bisect each other.&lt;/p&gt;&#xA;&lt;p&gt;&lt;strong&gt;Theorems 2–5 (tests for a parallelogram):&lt;/strong&gt; a quadrilateral is a parallelogram if its opposite sides are equal, or its opposite angles are equal, or its diagonals bisect each other, or one pair of opposite sides is both equal and parallel.&lt;/p&gt;</description>
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				<title>NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 12 Quadrilaterals Exercise Set 12.3</title>
				<link>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/exercise-set-12.3/</link>
				<pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
				<guid>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/exercise-set-12.3/</guid>
				<description>&lt;h1 id=&#34;ncert-solutions-for-class-9-maths-chapter-12--exercise-set-123&#34;&gt;NCERT Solutions for Class 9 Maths Chapter 12 — Exercise Set 12.3&lt;a class=&#34;anchor&#34; href=&#34;#ncert-solutions-for-class-9-maths-chapter-12--exercise-set-123&#34;&gt;#&lt;/a&gt;&lt;/h1&gt;&#xA;&lt;blockquote class=&#39;book-hint important&#39;&gt;&#xA;&lt;p&gt;&lt;strong&gt;Theorem 6 (Midpoint Theorem):&lt;/strong&gt; the segment joining the midpoints of two sides of a triangle is parallel to the third side and has half its length.&lt;/p&gt;&#xA;&lt;p&gt;&lt;strong&gt;Theorem 7 (Converse):&lt;/strong&gt; the line through the midpoint of one side, parallel to another side, bisects the third side.&lt;/p&gt;&#xA;&lt;p&gt;&lt;strong&gt;Theorem 9 (Varignon):&lt;/strong&gt; the midpoints of the four sides of a quadrilateral are the vertices of a parallelogram.&lt;/p&gt;</description>
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				<title>NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 12 Quadrilaterals Exercise Set 12.4</title>
				<link>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/exercise-set-12.4/</link>
				<pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
				<guid>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/exercise-set-12.4/</guid>
				<description>&lt;h1 id=&#34;ncert-solutions-for-class-9-maths-chapter-12--exercise-set-124&#34;&gt;NCERT Solutions for Class 9 Maths Chapter 12 — Exercise Set 12.4&lt;a class=&#34;anchor&#34; href=&#34;#ncert-solutions-for-class-9-maths-chapter-12--exercise-set-124&#34;&gt;#&lt;/a&gt;&lt;/h1&gt;&#xA;&lt;p&gt;In any tiling, the angles of the tiles that meet around a point must add up to exactly &lt;strong&gt;360°&lt;/strong&gt; — no gaps and no overlaps.&lt;/p&gt;&#xA;&lt;h2 id=&#34;1-justify-why-the-plane-cannot-be-tiled-with-a-regular-pentagon&#34;&gt;&lt;b class=&#34;normal-text&#34;&gt; 1. Justify why the plane cannot be tiled with a regular pentagon. &lt;/b&gt;&lt;a class=&#34;anchor&#34; href=&#34;#1-justify-why-the-plane-cannot-be-tiled-with-a-regular-pentagon&#34;&gt;#&lt;/a&gt;&lt;/h2&gt;&#xA;&lt;details&gt;&#xA;&lt;summary&gt;Solution&lt;/summary&gt;&lt;div class=&#34;markdown-inner book-answer-body&#34;&gt;&#xA;&lt;p&gt;Each angle of a regular pentagon is:&lt;/p&gt;&#xA;$$\dfrac{(5 - 2) \times 180°}{5} = 108°$$&lt;p&gt;Look at a corner of a tile. Around that point the angles must total 360°.&lt;/p&gt;</description>
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				<title>NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 12 Quadrilaterals End-of-Chapter Exercises</title>
				<link>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/end-of-chapter-exercises/</link>
				<pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
				<guid>https://padhaiwise.com/resources/class-9/ncert-solutions/maths-26/12-quadrilaterals/end-of-chapter-exercises/</guid>
				<description>&lt;h1 id=&#34;ncert-solutions-for-class-9-maths-chapter-12--end-of-chapter-exercises&#34;&gt;NCERT Solutions for Class 9 Maths Chapter 12 — End-of-Chapter Exercises&lt;a class=&#34;anchor&#34; href=&#34;#ncert-solutions-for-class-9-maths-chapter-12--end-of-chapter-exercises&#34;&gt;#&lt;/a&gt;&lt;/h1&gt;&#xA;&lt;blockquote class=&#39;book-hint important&#39;&gt;&#xA;&lt;p&gt;&lt;strong&gt;Parallelogram tests:&lt;/strong&gt; opposite sides equal; opposite angles equal; diagonals bisect each other; one pair of sides equal and parallel.&lt;/p&gt;&#xA;&lt;p&gt;&lt;strong&gt;Midpoint Theorem&lt;/strong&gt; and its &lt;strong&gt;converse (Theorem 7)&lt;/strong&gt;; &lt;strong&gt;Centroid Theorem&lt;/strong&gt; (medians meet at a point dividing each in the ratio 2 : 1); &lt;strong&gt;Varignon&amp;rsquo;s theorem&lt;/strong&gt;.&lt;/p&gt;&lt;/blockquote&gt;&lt;h2 id=&#34;1-using-a-fact-about-parallelograms-show-how-to-tile-the-plane-using-any-given-triangle-hint-can-you-use-the-parallelogram-tiling-in-the-introduction&#34;&gt;&lt;b class=&#34;normal-text&#34;&gt; 1. Using a fact about parallelograms, show how to tile the plane using any given triangle. (Hint: Can you use the parallelogram tiling in the introduction?) &lt;/b&gt;&lt;a class=&#34;anchor&#34; href=&#34;#1-using-a-fact-about-parallelograms-show-how-to-tile-the-plane-using-any-given-triangle-hint-can-you-use-the-parallelogram-tiling-in-the-introduction&#34;&gt;#&lt;/a&gt;&lt;/h2&gt;&#xA;&lt;details&gt;&#xA;&lt;summary&gt;Solution&lt;/summary&gt;&lt;div class=&#34;markdown-inner book-answer-body&#34;&gt;&#xA;&lt;p&gt;Take the triangle $ABC$ and a copy turned through 180° about the midpoint $M$ of side $BC$. The half-turn sends $B$ to $C$ and $C$ to $B$, and sends $A$ to a new point $D$ with $M$ the midpoint of $AD$.&lt;/p&gt;</description>
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