NCERT Solutions Class 10 Maths Chapter 7 Coordinate Geometry on Padhaiwise

NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Exercise 7.1

Mon, 01 Jan 0001 00:00:00 +0000

NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Exercise 7.1#

Exercise 7.1 focuses on the Distance Formula — finding the distance between two points given their coordinates, and using it to determine properties of geometric figures (collinearity, type of triangle/quadrilateral).

Distance Formula: The distance between two points $P(x_1, y_1)$ and $Q(x_2, y_2)$ is:
$$PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
Distance from Origin: Distance of point $P(x, y)$ from origin $= \sqrt{x^2 + y^2}$

NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Exercise 7.2

Mon, 01 Jan 0001 00:00:00 +0000

NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Exercise 7.2#

Exercise 7.2 covers the Section Formula — finding the coordinates of a point that divides a line segment in a given ratio, and its special case (midpoint formula).

Section Formula: The coordinates of point $P$ which divides the line segment joining $A(x_1, y_1)$ and $B(x_2, y_2)$ in ratio $m:n$ internally are:
$$P = \left(\frac{mx_2 + nx_1}{m+n},\ \frac{my_2 + ny_1}{m+n}\right)$$
Midpoint Formula: Midpoint of AB $= \left(\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2}\right)$