NCERT Solutions for Class 10 Maths Chapter 14 Probability Exercise 14.1

Mon, 01 Jan 0001 00:00:00 +0000

NCERT Solutions for Class 10 Maths Chapter 14 Probability Exercise 14.1#

Exercise 14.1 covers classical probability — finding the probability of events using coins, dice, cards, and balls in bags.

Classical Probability:
$$P(E) = \frac{\text{Number of outcomes favourable to } E}{\text{Total number of equally likely outcomes}}$$

$0 \leq P(E) \leq 1$
$P(E) + P(\bar{E}) = 1$
A standard deck has 52 cards: 4 suits (Hearts, Diamonds, Clubs, Spades), 13 each.

(i) Probability of an event E + Probability of the event ’not E’ = ___.

$P(E) + P(\bar{E}) = \mathbf{1}$