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		<title>NCERT Solutions Class 10 Maths Chapter 13 Statistics on Padhaiwise</title>
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				<title>NCERT Solutions for Class 10 Maths Chapter 13 Statistics Exercise 13.1</title>
				<link>https://padhaiwise.com/resources/class-10/ncert-solutions/maths-22/13-statistics/exercise-13.1/</link>
				<pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
				<guid>https://padhaiwise.com/resources/class-10/ncert-solutions/maths-22/13-statistics/exercise-13.1/</guid>
				<description>&lt;h1 id=&#34;ncert-solutions-for-class-10-maths-chapter-13-statistics-exercise-131&#34;&gt;NCERT Solutions for Class 10 Maths Chapter 13 Statistics Exercise 13.1&lt;a class=&#34;anchor&#34; href=&#34;#ncert-solutions-for-class-10-maths-chapter-13-statistics-exercise-131&#34;&gt;#&lt;/a&gt;&lt;/h1&gt;&#xA;&lt;p&gt;Exercise 13.1 covers three methods of finding the mean of grouped data: Direct Method, Assumed Mean Method, and Step Deviation Method.&lt;/p&gt;&#xA;&lt;blockquote class=&#39;book-hint info&#39;&gt;&#xA;&lt;p&gt;&lt;strong&gt;Methods to Find Mean of Grouped Data:&lt;/strong&gt;&lt;/p&gt;&lt;/blockquote&gt;&lt;ol&gt;&#xA;&lt;li&gt;&lt;strong&gt;Direct Method:&lt;/strong&gt; $\bar{x} = \dfrac{\sum f_i x_i}{\sum f_i}$&lt;/li&gt;&#xA;&lt;li&gt;&lt;strong&gt;Assumed Mean Method:&lt;/strong&gt; $\bar{x} = a &amp;#43; \dfrac{\sum f_i d_i}{\sum f_i}$, where $d_i = x_i - a$&lt;/li&gt;&#xA;&lt;li&gt;&lt;strong&gt;Step Deviation Method:&lt;/strong&gt; $\bar{x} = a &amp;#43; \dfrac{\sum f_i u_i}{\sum f_i} \times h$, where $u_i = \dfrac{x_i - a}{h}$&lt;/li&gt;&#xA;&lt;/ol&gt;&#xA;&lt;h2 id=&#34;1-a-survey-was-conducted-by-a-group-of-students-as-a-part-of-their-environment-awareness-programme-in-which-they-collected-the-following-data-regarding-the-number-of-plants-in-20-houses-in-a-locality-find-the-mean-number-of-plants-per-house&#34;&gt;&lt;b class=&#34;normal-text&#34;&gt; 1. A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house. &lt;/b&gt;&lt;a class=&#34;anchor&#34; href=&#34;#1-a-survey-was-conducted-by-a-group-of-students-as-a-part-of-their-environment-awareness-programme-in-which-they-collected-the-following-data-regarding-the-number-of-plants-in-20-houses-in-a-locality-find-the-mean-number-of-plants-per-house&#34;&gt;#&lt;/a&gt;&lt;/h2&gt;&#xA;&lt;details&gt;&#xA;&lt;summary&gt;Answer&lt;/summary&gt;&lt;div class=&#34;markdown-inner book-answer-body&#34;&gt;&#xA;&lt;table&gt;&#xA;&#x9;&lt;thead&gt;&#xA;&#x9;&#x9;&#x9;&lt;tr&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;th&gt;Number of plants&lt;/th&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;th&gt;Number of houses ($f_i$)&lt;/th&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;th&gt;$x_i$&lt;/th&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;th&gt;$f_i x_i$&lt;/th&gt;&#xA;&#x9;&#x9;&#x9;&lt;/tr&gt;&#xA;&#x9;&lt;/thead&gt;&#xA;&#x9;&lt;tbody&gt;&#xA;&#x9;&#x9;&#x9;&lt;tr&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;0-2&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;1&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;1&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;1&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&lt;/tr&gt;&#xA;&#x9;&#x9;&#x9;&lt;tr&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;2-4&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;2&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;3&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;6&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&lt;/tr&gt;&#xA;&#x9;&#x9;&#x9;&lt;tr&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;4-6&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;1&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;5&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;5&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&lt;/tr&gt;&#xA;&#x9;&#x9;&#x9;&lt;tr&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;6-8&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;5&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;7&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;35&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&lt;/tr&gt;&#xA;&#x9;&#x9;&#x9;&lt;tr&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;8-10&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;6&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;9&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;54&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&lt;/tr&gt;&#xA;&#x9;&#x9;&#x9;&lt;tr&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;10-12&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;2&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;11&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;22&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&lt;/tr&gt;&#xA;&#x9;&#x9;&#x9;&lt;tr&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;12-14&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;3&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;13&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;39&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&lt;/tr&gt;&#xA;&#x9;&#x9;&#x9;&lt;tr&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;&lt;strong&gt;Total&lt;/strong&gt;&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;&lt;strong&gt;20&lt;/strong&gt;&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&#x9;&#x9;&lt;td&gt;&lt;strong&gt;162&lt;/strong&gt;&lt;/td&gt;&#xA;&#x9;&#x9;&#x9;&lt;/tr&gt;&#xA;&#x9;&lt;/tbody&gt;&#xA;&lt;/table&gt;&#xA;&lt;p&gt;Using $\bar{x} = \dfrac{\sum f_i x_i}{\sum f_i}$:&#xA;&lt;/p&gt;</description>
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				<title>NCERT Solutions for Class 10 Maths Chapter 13 Statistics Exercise 13.2</title>
				<link>https://padhaiwise.com/resources/class-10/ncert-solutions/maths-22/13-statistics/exercise-13.2/</link>
				<pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
				<guid>https://padhaiwise.com/resources/class-10/ncert-solutions/maths-22/13-statistics/exercise-13.2/</guid>
				<description>&lt;h1 id=&#34;ncert-solutions-for-class-10-maths-chapter-13-statistics-exercise-132&#34;&gt;NCERT Solutions for Class 10 Maths Chapter 13 Statistics Exercise 13.2&lt;a class=&#34;anchor&#34; href=&#34;#ncert-solutions-for-class-10-maths-chapter-13-statistics-exercise-132&#34;&gt;#&lt;/a&gt;&lt;/h1&gt;&#xA;&lt;p&gt;Exercise 13.2 covers finding the mode of grouped data using the mode formula.&lt;/p&gt;&#xA;&lt;blockquote class=&#39;book-hint info&#39;&gt;&#xA;&lt;p&gt;&lt;strong&gt;Mode of Grouped Data:&lt;/strong&gt;&#xA;&lt;/p&gt;&#xA;$$\text{Mode} = l &amp;#43; \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h$$&lt;p&gt;&#xA;where $l$ = lower class limit of modal class, $f_1$ = frequency of modal class, $f_0$ = frequency of class preceding modal class, $f_2$ = frequency of class succeeding modal class, $h$ = class size.&lt;/p&gt;</description>
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				<title>NCERT Solutions for Class 10 Maths Chapter 13 Statistics Exercise 13.3</title>
				<link>https://padhaiwise.com/resources/class-10/ncert-solutions/maths-22/13-statistics/exercise-13.3/</link>
				<pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
				<guid>https://padhaiwise.com/resources/class-10/ncert-solutions/maths-22/13-statistics/exercise-13.3/</guid>
				<description>&lt;h1 id=&#34;ncert-solutions-for-class-10-maths-chapter-13-statistics-exercise-133&#34;&gt;NCERT Solutions for Class 10 Maths Chapter 13 Statistics Exercise 13.3&lt;a class=&#34;anchor&#34; href=&#34;#ncert-solutions-for-class-10-maths-chapter-13-statistics-exercise-133&#34;&gt;#&lt;/a&gt;&lt;/h1&gt;&#xA;&lt;p&gt;Exercise 13.3 covers finding the median of grouped data using the median formula.&lt;/p&gt;&#xA;&lt;blockquote class=&#39;book-hint info&#39;&gt;&#xA;&lt;p&gt;&lt;strong&gt;Median of Grouped Data:&lt;/strong&gt;&#xA;&lt;/p&gt;&#xA;$$\text{Median} = l &amp;#43; \frac{\frac{n}{2} - cf}{f} \times h$$&lt;p&gt;&#xA;where $l$ = lower class limit of median class, $n$ = total frequency, $cf$ = cumulative frequency of class preceding median class, $f$ = frequency of median class, $h$ = class size.&#xA;The median class is the class where cumulative frequency first exceeds $\dfrac{n}{2}$.&lt;/p&gt;</description>
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