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		<title>NCERT Solutions Class 10 Maths Chapter 11 Areas Related to Circles on Padhaiwise</title>
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				<title>NCERT Solutions for Class 10 Maths Chapter 11 Areas Related to Circles Exercise 11.1</title>
				<link>https://padhaiwise.com/resources/class-10/ncert-solutions/maths-22/11-areas-related-to-circles/exercise-11.1/</link>
				<pubDate>Mon, 01 Jan 0001 00:00:00 +0000</pubDate>
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				<description>&lt;h1 id=&#34;ncert-solutions-for-class-10-maths-chapter-11-areas-related-to-circles-exercise-111&#34;&gt;NCERT Solutions for Class 10 Maths Chapter 11 Areas Related to Circles Exercise 11.1&lt;a class=&#34;anchor&#34; href=&#34;#ncert-solutions-for-class-10-maths-chapter-11-areas-related-to-circles-exercise-111&#34;&gt;#&lt;/a&gt;&lt;/h1&gt;&#xA;&lt;p&gt;Exercise 11.1 covers areas of sectors, segments, and combinations of plane figures involving circles.&lt;/p&gt;&#xA;&lt;blockquote class=&#39;book-hint info&#39;&gt;&#xA;&lt;p&gt;&lt;strong&gt;Key Formulas:&lt;/strong&gt;&lt;/p&gt;&lt;/blockquote&gt;&lt;ul&gt;&#xA;&lt;li&gt;Length of arc $= \dfrac{\theta}{360°} \times 2\pi r$&lt;/li&gt;&#xA;&lt;li&gt;Area of sector $= \dfrac{\theta}{360°} \times \pi r^2$&lt;/li&gt;&#xA;&lt;li&gt;Area of minor segment $=$ Area of sector $-$ Area of triangle&lt;/li&gt;&#xA;&lt;li&gt;Use $\pi = \dfrac{22}{7}$ unless stated otherwise.&lt;/li&gt;&#xA;&lt;/ul&gt;&#xA;&lt;h2 id=&#34;1-find-the-area-of-a-sector-of-a-circle-with-radius-6-cm-if-angle-of-the-sector-is-60&#34;&gt;&lt;b class=&#34;normal-text&#34;&gt; 1. Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°. &lt;/b&gt;&lt;a class=&#34;anchor&#34; href=&#34;#1-find-the-area-of-a-sector-of-a-circle-with-radius-6-cm-if-angle-of-the-sector-is-60&#34;&gt;#&lt;/a&gt;&lt;/h2&gt;&#xA;&lt;details&gt;&#xA;&lt;summary&gt;Answer&lt;/summary&gt;&lt;div class=&#34;markdown-inner book-answer-body&#34;&gt;&#xA;&lt;div id=&#34;geom-1&#34; class=&#34;jxgbox&#34; data-geom&gt;&lt;/div&gt;&#xA;&lt;script type=&#34;application/json&#34; id=&#34;geom-1-spec&#34;&gt;&#xA;{&#xA;  &#34;boundingbox&#34;: [-7, 7, 7, -7],&#xA;  &#34;axis&#34;: false,&#xA;  &#34;elements&#34;: [&#xA;    {&#34;type&#34;: &#34;point&#34;, &#34;id&#34;: &#34;O&#34;, &#34;coords&#34;: [0, 0], &#34;name&#34;: &#34;O&#34;, &#34;options&#34;: {&#34;label&#34;: {&#34;offset&#34;: [-14, -4]}}},&#xA;    {&#34;type&#34;: &#34;circle&#34;, &#34;center&#34;: &#34;O&#34;, &#34;radius&#34;: 6, &#34;color&#34;: &#34;#2f6fda&#34;},&#xA;    {&#34;type&#34;: &#34;point&#34;, &#34;id&#34;: &#34;A&#34;, &#34;coords&#34;: [6, 0], &#34;name&#34;: &#34;A&#34;, &#34;options&#34;: {&#34;label&#34;: {&#34;offset&#34;: [6, -4]}}},&#xA;    {&#34;type&#34;: &#34;point&#34;, &#34;id&#34;: &#34;B&#34;, &#34;coords&#34;: [3, 5.196], &#34;name&#34;: &#34;B&#34;, &#34;options&#34;: {&#34;label&#34;: {&#34;offset&#34;: [4, 6]}}},&#xA;    {&#34;type&#34;: &#34;segment&#34;, &#34;points&#34;: [&#34;O&#34;, &#34;A&#34;], &#34;color&#34;: &#34;#e2733a&#34;},&#xA;    {&#34;type&#34;: &#34;segment&#34;, &#34;points&#34;: [&#34;O&#34;, &#34;B&#34;], &#34;color&#34;: &#34;#e2733a&#34;},&#xA;    {&#34;type&#34;: &#34;angle&#34;, &#34;points&#34;: [&#34;A&#34;, &#34;O&#34;, &#34;B&#34;], &#34;name&#34;: &#34;60°&#34;, &#34;options&#34;: {&#34;radius&#34;: 1.2, &#34;fillColor&#34;: &#34;#c44a76&#34;}},&#xA;    {&#34;type&#34;: &#34;text&#34;, &#34;coords&#34;: [3, -0.4], &#34;text&#34;: &#34;6 cm&#34;, &#34;options&#34;: {&#34;color&#34;: &#34;#e2733a&#34;, &#34;anchorX&#34;: &#34;middle&#34;}}&#xA;  ]&#xA;}&#xA;&lt;/script&gt;&#xA;&lt;p&gt;Using Area of sector $= \dfrac{\theta}{360°} \times \pi r^2$, we find the area:&#xA;&lt;/p&gt;</description>
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